Chương trình đọc số có 3 chữ số.

by thanhvu215 Mon May 09, 2011 9:16 pm

#include
#include
void main()
{
int a;
cout<<"Nhap vao mot so co 3 hay 2 tham chi 1 chu so: ";
cin>>a;
int hangtram=a/100;
int hangchuc=((a/10)%10);
int hangdonvi=a%10;
switch(hangtram)
{
case 1 :cout<<"Mot tram ";break;
case 2 :cout<<"Hai tram ";break;
case 3 :cout<<"Ba tram ";break;
case 4 :cout<<"Bon tram ";break;
case 5 :cout<<"Nam tram ";break;
case 6 :cout<<"Sau tram ";break;
case 7 :cout<<"Bay tram ";break;
case 8 :cout<<"Tam tram ";break;
case 9 :cout<<"Chin tram ";break;
}
switch(hangchuc)
{
case 0:
if(hangdonvi==0)
cout<<"";
else
{if(hangchuc==0&&hangtram==0)
cout<<"";
else
cout<<"ninh";}
break;
case 1:cout<<"muoi";break;
case 2:cout<<"hai muoi";break;
case 3:cout<<"ba muoi";break;
case 4:cout<<"bon muoi";break;
case 5:cout<<"nam muoi";break;
case 6:cout<<"sau muoi";break;
case 7:cout<<"bay muoi";break;
case 8:cout<<"tam muoi";break;
case 9:cout<<"chin muoi";break;
}
switch(hangdonvi)
{
case 0:cout<<"Khong";break;
case 1:
if(hangchuc==1||(hangtram==0&&hangchuc==0))
cout<<" mot";
else
cout<<" mo't";
break;
case 2:cout<<" hai";break;
case 3:cout<<" ba";break;
case 4:
if(hangchuc==1)
cout<<" bon";
else
{if(hangchuc==0&&hangtram==0)
cout<<"bon";
else
cout<<" tu";}
break;
case 5:
if(hangchuc==0&&hangtram==0)
cout<<" nam";
else
cout<<" lam";
break;
case 6:cout<<" sau";break;
case 7:cout<<" bay";break;
case 8:cout<<" tam";break;
case 9:cout<<" chin";break;
}
getch();
}

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